# Wipro Paper Pattern

WIPRO Placement Paper

PART A

1) abcD+abcd+aBCd+aBCD then the simplified function is ( Capital letters are copliments of corresponding letters A=compliment of a)

[a] a

[b] ab

[c] abc

[d] a(bc)*

[e] None (bc)*=compliment of bc

Ans: e

2) A 12 address lines maps to the memory of

[a] 1k bytes

[b] 0.5k bytes

[c] 2k bytes

[d] none

Ans: b

3) In a processor these are 120 instructions . Bits needed to implement this instructions

[a] 6

[b] 7

[c] 10

[d] none

Ans: b

4) In 8085 microprocessor READY signal does.which of the following is incorrect statements

[a] It is input to the microprocessor

[b] It sequences the instructions.

Ans : b

5) Return address will be returned by function to :

Ans : Pushes to the stack by call

6) n=7623

{temp=n/10; result=temp*10+ result; n=n/10 }

Ans : 3267

7) If A>B then

F=F(G);

else B>C then

F=G(G);

in this , for 75% times A>B and 25% times B>C then,is 10000 instructions are there ,then the ratio of F to G

[a] 7500:2500

[b] 7500:625

[c] 7500:625 if a=b=c else 7500:2500

8) In a compiler there is 36 bit for a word and to store a character 8bits are needed. IN this to store a character two words are appended .Then for storing a K characters string, How many words are needed.

[a] 2k/9

[b] (2k+8)/9

[c] (k+8)/9

[d] 2*(k+8)/9

[e] none

Ans: a

9) C program code

int zap(int n)

{

if(n<=1)then zap=1;

More

else zap=zap(n3)+zap(n1);

}

then the call zap(6) gives the values of zap

[a] 8

[b] 9

[c] 6

[d] 12

[e] 15

Ans: b

PART B

1) Virtual memory size depends on

[a] address lines

[b] data bus

[c] disc space

[d] a & c [e] none

Ans : a

2) Load a

mul a

store t1

load b

mul b

store t2

mul t2

add t1

Then the content in accumulator is

Ans : a**2+b**4

PART A

1) abcD+abcd+aBCd+aBCD then the simplified function is ( Capital letters are copliments of corresponding letters A=compliment of a)

[a] a

[b] ab

[c] abc

[d] a(bc)*

[e] None (bc)*=compliment of bc

Ans: e

2) A 12 address lines maps to the memory of

[a] 1k bytes

[b] 0.5k bytes

[c] 2k bytes

[d] none

Ans: b

3) In a processor these are 120 instructions . Bits needed to implement this instructions

[a] 6

[b] 7

[c] 10

[d] none

Ans: b

4) In 8085 microprocessor READY signal does.which of the following is incorrect statements

[a] It is input to the microprocessor

[b] It sequences the instructions.

Ans : b

5) Return address will be returned by function to :

Ans : Pushes to the stack by call

6) n=7623

{temp=n/10; result=temp*10+ result; n=n/10 }

Ans : 3267

7) If A>B then

F=F(G);

else B>C then

F=G(G);

in this , for 75% times A>B and 25% times B>C then,is 10000 instructions are there ,then the ratio of F to G

[a] 7500:2500

[b] 7500:625

[c] 7500:625 if a=b=c else 7500:2500

8) In a compiler there is 36 bit for a word and to store a character 8bits are needed. IN this to store a character two words are appended .Then for storing a K characters string, How many words are needed.

[a] 2k/9

[b] (2k+8)/9

[c] (k+8)/9

[d] 2*(k+8)/9

[e] none

Ans: a

9) C program code

int zap(int n)

{

if(n<=1)then zap=1;

More

else zap=zap(n3)+zap(n1);

}

then the call zap(6) gives the values of zap

[a] 8

[b] 9

[c] 6

[d] 12

[e] 15

Ans: b

PART B

1) Virtual memory size depends on

[a] address lines

[b] data bus

[c] disc space

[d] a & c [e] none

Ans : a

2) Load a

mul a

store t1

load b

mul b

store t2

mul t2

add t1

Then the content in accumulator is

Ans : a**2+b**4

Wipro Paper Pattern
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