13 October 2015

HCL Placement Paper and Pattern (Technical)

Section I: computer awareness 
Section II: Simple C- language 
Section III: On pointers & structures and C++, JAVA(only 1 on this) 
Section IV: Analytical 
  1. Which of the following involves context switch,
(a) system call (b) privileged instruction) floating point exception) all the above (e) none of the above
Ans: (a)
2. In OST, terminal emulation is done in
(a) sessions layer b) application layer c) presentation layer (d) transport layer
Ans: (b)
3. For a 25MHz processor , what is the time taken by the instruction which needs 3 clock cycles,
(a)120 nano secs(b)120 micro secs(c)75 nano secs(d)75 micro secs ans a
4. For 1 MB memory, the number of address lines required,
(a)11 (b)16 (c)20(d) 24
Ans. (c)
5. Semaphore is used for
(a) synchronization b) dead-lock avoidance (c) box (d) none
Ans. (a)
6. Parity error checking is used for.........?
Ans: a odd numbers of errors
7. Address on internet are (Internet IP address is unique for..)
a) unique for particular domain
b) unique for a particular sub-node list
c) unique countrywide
d) unique in a network area
Ans: b has to be unique in the sub network
8. one ans is c Volatile modifier
9. OLE is used in
a) inter connection in Unix
b) interconnection in WINDOWS
c) interconnection in WINDOWS NT
ans c(check)
10. Convert a given HEX number to OCTAL
  11. Macros and function are related in what aspect?
(a) recursion
(b) varying no of arguments
(c) hypo checking
(d) type declaration
Ans d or a (check)
12.Preprocessor does not do which one of the following
(a) macro
(b) conditional complication
(c) in type checking
(d) including load file
Ans. (c)
13. Piggy backing is a technique for
a) Flow control
b) Sequence
c) Acknowledgement
d) retransmission
Ans. (c)
14. In signed magnitude notation what is the minimum
value that can be represented with 8 bits
(a) -128
(b) -255
(c) -127
(d) 0
Ans a
15. There is an employer table with key fields as employer number data in every n'th row are needed for a simple following queries will get required results.
(a) select A employee number from employee A , w here exists from employee B where A employee no. = B employee having (count(*) mod n)=0
(b) select employee number from employe A, employe B where A employe number=B employ number group by employee number having(count(*) mod n=0 )
(c) both (a) & (b)
(d) none of the above
15. Type duplicates of a row in a table customer with on uniform key field customer number you can see
a) delete from customer where customer number exists (select distinct customer number from customer having count )
b) delete customer a where customer number in b rowid 

c) delete customer a where customer number in( select customer number from customer a, customer b )
d) none of the above

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